5h^2+18h+4-7h+h^2=0

Solution for 5h^2+18h+4-7h+h^2=0 equation:

5h^2+18h+4-7h+h^2=0

We add all the numbers together, and all the variables

6h^2+11h+4=0

a = 6; b = 11; c = +4;
Δ = b2-4ac
Δ = 112-4·6·4
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-5}{2*6}=\frac{-16}{12}
=-1+1/3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+5}{2*6}=\frac{-6}{12}
=-1/2
$